This article demonstrates some commonly asked SQL queries in a job interview. I will be covering some of the common but tricky queries like:-
To find the nth highest salary, replace the top 3 with top n (n being an integer 1,2,3 etc.)
Now, if you want to select top 2 records from each group, the query is as follows:-
This can be achieved in tow ways :-
(a) Using a temporary table.
(b) Without using a temporary table.
(i) Finding the nth highest salary of an employee.
(ii) Finding TOP X records from each group.
(iii) Deleting duplicate rows from a table.
NOTE : All the SQL mentioned in this article has been tested under SQL Server 2005. (ii) Finding TOP X records from each group.
(iii) Deleting duplicate rows from a table.
(i) Finding the nth highest salary of an employee.
Create a table named Employee_Test and insert some test data as:-CREATE TABLE Employee_Test ( Emp_ID INT Identity, Emp_name Varchar(100), Emp_Sal Decimal (10,2) ) INSERT INTO Employee_Test VALUES ('Anees',1000); INSERT INTO Employee_Test VALUES ('Rick',1200); INSERT INTO Employee_Test VALUES ('John',1100); INSERT INTO Employee_Test VALUES ('Stephen',1300); INSERT INTO Employee_Test VALUES ('Maria',1400);It is very easy to find the highest salary as:-
--Highest Salary select max(Emp_Sal) from Employee_TestNow, if you are asked to find the 3rd highest salary, then the query is as:-
--3rd Highest Salary select min(Emp_Sal) from Employee_Test where Emp_Sal in (select distinct top 3 Emp_Sal from Employee_Test order by Emp_Sal desc)The result is as :- 1200
To find the nth highest salary, replace the top 3 with top n (n being an integer 1,2,3 etc.)
--nth Highest Salary select min(Emp_Sal) from Employee_Test where Emp_Sal in (select distinct top n Emp_Sal from Employee_Test order by Emp_Sal desc)
(ii) Finding TOP X records from each group
Create a table named photo_test and insert some test data as :-create table photo_test ( pgm_main_Category_id int, pgm_sub_category_id int, file_path varchar(MAX) ) insert into photo_test values (17,15,'photo/bb1.jpg'); insert into photo_test values(17,16,'photo/cricket1.jpg'); insert into photo_test values(17,17,'photo/base1.jpg'); insert into photo_test values(18,18,'photo/forest1.jpg'); insert into photo_test values(18,19,'photo/tree1.jpg'); insert into photo_test values(18,20,'photo/flower1.jpg'); insert into photo_test values(19,21,'photo/laptop1.jpg'); insert into photo_test values(19,22,'photo/camer1.jpg'); insert into photo_test values(19,23,'photo/cybermbl1.jpg'); insert into photo_test values (17,24,'photo/F1.jpg');There are three groups of pgm_main_category_id each with a value of 17 (group 17 has four records),18 (group 18 has three records) and 19 (group 19 has three records).
Now, if you want to select top 2 records from each group, the query is as follows:-
select pgm_main_category_id,pgm_sub_category_id,file_path from ( select pgm_main_category_id,pgm_sub_category_id,file_path, rank() over (partition by pgm_main_category_id order by pgm_sub_category_id asc) as rankid from photo_test ) photo_test where rankid < 3 -- replace 3 by any number 2,3 etc for top2 or top3. order by pgm_main_category_id,pgm_sub_category_idThe result is as:-
pgm_main_category_id pgm_sub_category_id file_path 17 15 photo/bb1.jpg 17 16 photo/cricket1.jpg 18 18 photo/forest1.jpg 18 19 photo/tree1.jpg 19 21 photo/laptop1.jpg 19 22 photocamer1.jpg
(iii) Deleting duplicate rows from a table
A table with a primary key doesn’t contain duplicates. But if due to some reason, the keys have to be disabled or when importing data from other sources, duplicates come up in the table data, it is often needed to get rid of such duplicates.This can be achieved in tow ways :-
(a) Using a temporary table.
(b) Without using a temporary table.
(a) Using a temporary or staging table
Let the table employee_test1 contain some duplicate data like:-CREATE TABLE Employee_Test1 ( Emp_ID INT, Emp_name Varchar(100), Emp_Sal Decimal (10,2) ) INSERT INTO Employee_Test1 VALUES (1,'Anees',1000); INSERT INTO Employee_Test1 VALUES (2,'Rick',1200); INSERT INTO Employee_Test1 VALUES (3,'John',1100); INSERT INTO Employee_Test1 VALUES (4,'Stephen',1300); INSERT INTO Employee_Test1 VALUES (5,'Maria',1400); INSERT INTO Employee_Test1 VALUES (6,'Tim',1150); INSERT INTO Employee_Test1 VALUES (6,'Tim',1150);Step 1: Create a temporary table from the main table as:-
select top 0* into employee_test1_temp from employee_test1Step2 : Insert the result of the GROUP BY query into the temporary table as:-
insert into employee_test1_temp select Emp_ID,Emp_name,Emp_Sal from employee_test1 group by Emp_ID,Emp_name,Emp_SalStep3: Truncate the original table as:-
truncate table employee_test1Step4: Fill the original table with the rows of the temporary table as:-
insert into employee_test1 select * from employee_test1_tempNow, the duplicate rows from the main table have been removed.
select * from employee_test1gives the result as:-
Emp_ID Emp_name Emp_Sal 1 Anees 1000 2 Rick 1200 3 John 1100 4 Stephen 1300 5 Maria 1400 6 Tim 1150
(b) Without using a temporary table
;with T as ( select * , row_number() over (partition by Emp_ID order by Emp_ID) as rank from employee_test1 ) delete from T where rank > 1The result is as:-
Emp_ID Emp_name Emp_Sal 1 Anees 1000 2 Rick 1200 3 John 1100 4 Stephen 1300 5 Maria 1400 6 Tim 1150
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